# How to Find the Equation of a Line Given Two Points

### Linear Equations and Graphing

In math and science we are sometimes given a set of data and need to determine an equation to describe the relationship between them. In this lesson we look at how to find the equation of a line given 2 points.

One real life situation happened when rangers tried to predict how often the geyser Old Faithful would erupt.

#### Your turn:   How do you find the equation of the line through points:

$$\color{#9400d3}{(-3,5)(2,1)}$$

#### Solution:

To solve this problem we will start with a equation for a line. I prefer to use the slope-intercept form: $\color{#9400d3}{y=mx+b}$.

Next we need to find the slope (m) of the line.
$$\color{#9400d3}{m = \frac{\Delta y}{\Delta x} = \frac{5-1}{-3-2} = \frac{4}{-5}}$$

Now we need to fine the y-intercept. To do that we will pick a point that is on the line, we could use either $(-3,5)$ or $(2,1)$. It does not matter which pair we use, that other pair will be used in checking our equation. Lets use $\color{#9400d3}{(2,1)}$ to determine the y-intercept.

\begin{align*} y &= \color{#9400d3}{\frac{-4}{5}}x + b\\ \\[1px] \color{#9400d3}1 &= \frac{-4}{5}*\color{#9400d3}2+b\\ \\[1px] 1 &= \frac{-8}{5}*\color{#9400d3}+b\\ \\[1px] 1 \color{fuchsia}{+\frac{8}{5}} &= \frac{-8}{5}\color{fuchsia}{+\frac{8}{5}}+b\\ \\[1px] \color{#9400d3}{\frac{13}{5}} &= b\\ \\[1px] \color{#9400d3}b &= \color{#9400d3}{2\frac{3}{5}} \end{align*}

Our final step is to add the y-intercept (b) into the formula.

$$\color{#9400d3}{y = {\frac{-4}{5}}x + 2\frac{3}{5}}$$

#### Check:

There two ways we can check this equation.

1. by substituting in (-3,5) into the equation and making sure it leads to a true statement (be sure to use the coordinates of the point not used to find the y-intercept.)
\begin{align*} y &= {\frac{-4}{5}}x + 2\frac{3}{5}\\ \\[1px] \color{#9400d3}5 &= \frac{-4}{5}*\color{#9400d3}{^-3} + 2\frac{3}{5}\\ \\[1px] 5 &= 2\frac{2}{5}+ 2\frac{3}{5}\\ \\[1px] 5 &= 5 \end{align*}
2.The other way would be to graph the two original points.

Looking at the graph we can see the y-intercept is approximately $2\frac{2}{5}$,
and the slope is $\frac{-4}{5}$.